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31 December, 23:38

When the pumpkin is shot straight upward with an initial speed of 14 m/s, what is the maximum height above its initial equation

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  1. 1 January, 00:50
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    10 m

    Explanation:

    At the maximum height, the velocity is 0.

    Given:

    v₀ = 14 m/s

    v = 0 m/s

    a = - 9.8 m/s²

    Find: Δy

    v² = v₀² + 2aΔy

    (0 m/s) ² = (14 m/s) ² + 2 (-9.8 m/s²) Δy

    Δy = 10 m
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