A railroad freight car of mass 3.34 * 104 kg collides with a stationary caboose car. They couple together, and 19.0% of the initial kinetic energy is transferred to thermal energy, sound, vibrations, and so on. Find the mass of the caboose.

4.123 * 10∧4 kg

Explanation:

mass of car M' = 3.34 * 10∧4 kg

energy loss E = 19/100 K

from law of conservation of momentum,

M' V' = (M' + M'') v

V = M' V' / (M' + M'')

Initial kinetic energy is K' = (M' V') ² / 2

final kinetic energy K" = 81 K' / 100

= (M' V') ² 81 / (200) = (M' + M'') v² / 2

therefore, M' / (M' + M") = 0.81

mass of caboose is, M" = 1.234 M' - M'

M" =.234 M'

= 0,234 (3.34 * 10∧4 kg)

= 4.123 * 10∧4 kg