Ask Question
14 February, 02:11

A solution of phosphoric acid was made by dissolving 10.0 g H3PO4 in 100.0 mL water. The resulting volume was 104 mL. Calculate the density, mole fraction, molarity, and molality of the solution. Assume water has a density of 1.00 g/cm3.

+5
Answers (1)
  1. 14 February, 05:33
    0
    density is 1.057 g/mL

    mole fraction is 0.0180

    molarity is 0.98 mol/L

    mole fraction is 0.0180

    Explanation:

    Given data

    acid mass = 10 g

    water volume = 100 mL

    total volume = 104 mL

    density = 1 g/cm³

    to find out

    the density, mole fraction, molarity, and molality

    solution

    first we calculate the density that is = total mass g / volume of solution mL

    total mass = mass of H3PO4 + water mass

    so water mass = density x volume

    water mass = 100 ml x 1.0 g/cm3

    water mass = 100 g

    so total mass = 110.00 g

    so that

    density = total mass g / volume of solution mL

    density = 110 / 104 = 1.057 g/mL

    now we calculate no of moles in solvent i. e = mass H2O / mlar mass H2O

    no of moles in solvent = 100/18.015 = 5.55 moles

    and no of moles in solute i. e = mass of H3PO4 / mlar mass in H3PO4

    moles in solute i. e = 10 / 97.994 = 0.102 moles

    so total moles is 5.55 + 0.102 = 5.652 moes

    so now mole fraction = no of moles in solute / total moes

    mole fraction = 5.55 / 5.65

    mole fraction is 0.0180

    now we calculate first

    mole fraction in solute and solvent that is

    mole fraction in solute = no of moles in solute / total moles

    mole fraction in solute = 0.102 / 5.65

    mole fraction in solute is 0.0180

    and mole fraction in solvent that = no of moles in solvent / total moles

    mole fraction in solvent that = 5.55 / 5.65

    mole fraction in solvent that is 0.982

    so molarity = no of moles of solute / volume

    molarity = 0.102/0.104

    molarity is 0.98 mol/L

    and molality is = no of moles of solute / mass

    molality = 0.102 / 100

    molality is 1.02 mol/kg
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A solution of phosphoric acid was made by dissolving 10.0 g H3PO4 in 100.0 mL water. The resulting volume was 104 mL. Calculate the ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers