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19 June, 12:32

A particle with a mass of 2.3 * 10-20 kg is oscillating with simple harmonic motion with a period of 3.0 * 10-5 s and a maximum speed of 2.2 * 103 m/s. Calculate (a) the angular frequency and (b) the maximum displacement of the particle.

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  1. 19 June, 14:57
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    angular frequency is 209439.51 rad/sec

    maximum displacement is 0.010504 m

    Explanation:

    Given data

    mass = 2.3 * 10^-20 kg

    period = 3.0 * 10^-5 s

    maximum speed = 2.2 * 10^3 m/s

    to find out

    the angular frequency and maximum displacement

    solution

    we know angular frequency formula that is

    angular frequency = 2 π / period

    put here period value we get angular frequency

    angular frequency = 2 π / 3.0 * 10^-5

    angular frequency is 209439.51 rad/sec

    maximum displacement formula is

    speed = angular frequency * maximum displacement

    put all value and we get maximum displacement

    maximum displacement = 2.2 * 10^3 / 209439.51

    maximum displacement is 0.010504 m
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