How much heat is absorbed by 62g iron skillet when it's temperature rises from 8c to 27c

530 J

Explanation:

Heat absorbed is:

q = mCΔT

where m is mass, C is the specific heat, and ΔT is the temperature increase.

The specific heat of iron is 0.449 J/g/C. Therefore:

q = (62 g) (0.449 J/g/C) (27°C - 8°C)

q ≈ 529 J

Rounded to two significant figures, the heat absorbed is approximately 530 J.