A 75.0 kg students sits 1.15 m away from a 68.4 kg student. What is the force of gravitational attraction between them?

Give answer in scientific notation.

F=2.589*10⁻⁷ Newtons

Explanation:

The gravitational force of attraction between two bodies is given by

F = Gm₁m₂/r²

Where m₁ and m₂ are the masses of the two bodies, G is the universal gravitational constant while r is the distance between the two bodies.

G=6.67408 * 10⁻¹¹m³kg⁻¹s⁻²

r=1.15m

m₁=75.0kg

m₂=68.4kg

Therefore F = (6.67408*10⁻¹¹m³kg⁻¹s⁻²*75.0kg*68.4kg) / (1.15m) ²

F=2.589*10⁻⁷ Newtons