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7 October, 02:53

Water with pressure of 190 kPa flows down hill through a pipe with a 3.90 cm diameter hose at a speed of 1.2 m/s. It then exits through a smaller pipe m of diameter 1.50 cm which is 5.00 m below the upper pipe.

a. What is the speed of the water exiting at the lower pipe opening?

b. What is the water pressure at the exit of the lower pipe.?

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  1. 7 October, 06:31
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    a) v₂ = 8,112 m / s, b) P₂ = 206.8 10³ Pa

    Explanation:

    This is a fluid mechanics exercise, let's use index 1 for thick pipe and index 2 for thinner pipe

    a) with the continuity equation it allows to find the speed of the water

    v₁ A₁ = v₂ A₂

    the area of a circle is

    A₁ = π r₁² = π d₁² / 4

    v₂ = v₁ d₁² / d₂²

    let's calculate

    v₂ = 1.2 3.90² / 1.50²

    v₂ = 8,112 m / s

    b) We use Bernoulli's equation

    P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂

    P2 = P1 + ½ ρ (v₁² - v₂²) + ρ g (y₁ - y₂)

    let's calculate

    P₂ = 190 10³ + ½ 1000 (1.2² - 8.112²) + 1000 9.8 5

    P₂ = 206.8 10³ Pa
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