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25 April, 19:01

Tectonic plates are large segments of the earth's crust that move slowly. Suppose one such plate has an average speed of 6.0 cm per year.

(a) What distance does it move in 25 seconds at this speed?

What's the formula for this problem?

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Answers (1)
  1. 25 April, 20:33
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    For this problem, we use the following expression:

    Speed = distance / time

    Distance = Speed * time

    Since the problem tells us the speed of the plates, we know that

    Speed_plates = 6.0 cm/year

    Which is equal to

    Speed_plates = 6.0 cm/365 days = 6.0 cm / (365*24 hours)

    Speed_plates = 6.0 cm / (365*24*60 minutes)

    Speed_plates = 6.0 cm / (365*24*60*60 seconds)

    Speed_plates = 190.258 E - 9 cm / s

    We multiply by 25, to get the distance traveled after 25 seconds

    Distance traveled = 4.756 E-6 cm
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