An object with a mass of 450. grams is dropped off a 706m cliff. What is the velocity of the rock right before it impacts the ground.

Correct answer: V = 118.83 m/s

Explanation:

Given:

m = 450 g = 0.45 kg mass of the object

H = 706 m the height of the cliff from which the object was dropped

V = ? final velocity before object impact the ground

This movement is a free fall.

The velocity is calculated using the following formula:

V² = 2 · g · H in calculating we will use g = 10 m/s²

V² = 2 · 10 · 706 = 14,120 ⇒ V = √14,120 = 118.83 m/s

V = 118.83 m/s

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