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23 December, 01:57

Reacting with water in an acidic solution at a particular temperature, compound A decomposes into compounds B and C according to the law of uninhibited decay. An initial amount of 0.60 M of compound A decomposes to 0.56 M in 30 minutes. How much of compound A will remain after 3 hours? How long will it take until 0.10 M of compound A remains?

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  1. 23 December, 03:49
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    after t = 3 hours compound A remain 0.396 M

    t = 12.98 hours

    Explanation:

    P = P_0*e^ (-kt)

    t = 30 minutes = 30/60 hours = 0.5 hours

    and P_0 = 0.60M

    and P after t = 0.5 hours is 0.56 M

    (0.56/0.6) = e^ (-kt)

    0.933 = e^ (-kt)

    k = 0.138

    P = P_0*e^ (-0.138t)

    Now after t = 3 hours,

    P = 0.6 * e^ ((-0.138) * 3) = 0.396 M

    time when P = 0.1 M

    0.1 = 0.6*e^ (-0.138t)

    t = 12.98 hours
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