Consider the inelastic collision. Two lumps of matter are moving directly toward each other. Each lump has a mass of 1.500 kg 1.500 kg and is moving at a speed of 0.930 c 0.930c. The two lumps collide and stick together. Answer the questions, keeping in mind that relativistic effects cannot be neglected in this case. What is the final speed v f vf of the combined lump, expressed as a fraction of c?

Question

Physics

Logan Fletcher

14 March, 10:52

Consider the inelastic collision. Two lumps of matter are moving directly toward each other. Each lump has a mass of 1.500 kg 1.500 kg and is moving at a speed of 0.930 c 0.930c. The two lumps collide and stick together. Answer the questions, keeping in mind that relativistic effects cannot be neglected in this case. What is the final speed v f vf of the combined lump, expressed as a fraction of c?

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Answers (1)

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Phillip Bailey · Answer 1

The final velocity after impact of the combine lump is

V=0.930m/s

Explanation:

Step one

This type of collision is an inelastic types of collision. The total energy of the colliding bodies is conserved or when the bodies stick together and move with a common velocity

Step two

Given data

M1 = 1500kg

M2=1500kg

U1=0.930m/s

U2=0.930m/s

V=?

Step three

Applying momentum equation we have

Total momentum before impact

=M1U1+M2U2

Total momentum after impact

= (M1+M2) V

According to the principle of conservation of momentum

M1U1+M2U2 = (M1+M2) V

Substituting our data into the expression we have

1500*0.930+1500*0.930=

(1500+1500) V

1395+1395=3000V

2790=3000V

V=2790/3000

V=0.930m/s