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16 July, 12:40

A car traveling at 27 m/s starts to decelerate steadily. It comes to a complete stop in 14 seconds. What is its acceleration?

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  1. 16 July, 16:07
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    You will need to use this formula:

    V = Vo + a x t

    V - Final velocity / / If it comes to a complete stop, it will be 0 m/s.

    Vo - Initial velocity = 27 m/s

    a - Acceleration = ? m/s^2 / / All units are in S. I

    t - Time = 14 secs

    So:

    -> 0 = 27 + a x 14

    -> 14a + 27 = 0

    -> 14a = - 27

    -> a = - 27/14

    -> a = - 1.928 ... m/s^2

    Rounding to the nearest hundredth: - 1.93 m/s^2.

    Answer: The acceleration of the car is - 1.93 m/s^2.
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