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28 November, 13:21

An arrow is fired directly upwards at 15m/s from the ground level.

A: How long is the arrow in the air?

B: How high does the arrow go?

C: How fast is it going just before it strikes the ground?

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Answers (1)
  1. 28 November, 15:26
    0
    Given that,

    Initial Velocity, Vi = 15 m/s

    acceleration due to gravity, g = 9.81 m/s²

    Time in air, t = ?

    Height, h = ?

    Speed before striking ground, Vf = ?

    Since, we know that,

    2as = Vf² - Vi²

    2 * (-9.81) * s = 0 - 15²

    solving above equation we have,

    s = 11.46 m

    or

    h = 11.46 m

    Height achieve by arrow will be 11.46 m

    Since,

    s = Vt

    t = s / V

    t = 11.46 / 15

    t = 0.76

    Total time in air = 2 * t = 2*0.76

    Time in air will be 1.53 s

    Since,

    2as = Vf² - Vi²

    2*9.81 * 11.46 = Vf² - 0

    solving above equation we have,

    Vf = 14.99 m/s

    or

    Velocity of arrow just before striking ground will be 15 m/s approximately.
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