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29 July, 00:22

The amount of electric energy consumed by a 60.0-watt lightbulb for 1.00 minute could lift a

10.0-newton object to a maximum vertical height of

A) 6.00 m B) 36.7 m C) 360. m D) 600. M

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  1. 29 July, 00:28
    0
    Given that,

    Amount of energy consumed by a 60W light bulb for 1 minutes

    P = 60 W

    t = 1 mins = 60seconds

    This energy can be used to lift a body that weight 10N

    W = 10N

    This shows that the electrical energy is converted to potential energy

    Let calculate the electrical energy

    Power is the rate of doing work

    Power = Work / time

    Therefore, work = power * time

    Work = 60 * 60

    Work = 3600 J

    Potential energy can be calculated using

    P. E = mgh

    Where, weight is

    W = mg

    Then, P. E = W•h

    P. E = 10•h

    Then,

    Potential energy, = Electrical energy

    P. E = Work

    10•h = 3600

    Divide both sides by 10

    h = 3600 / 10

    h = 360m

    So, the object will be lifted to a height of 360m
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