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26 September, 06:39

The overall reaction in the lead storage battery is: Pb (s) + PbO2 (s) + 2 H + (aq) + 2 HSO4 - (aq)  2 PbSO4 (s) + 2 H2O (l) Calculate the potential at 310 K for this battery when [H + ] = [HSO4 - ] = 4.5 M. At 310 K E o = 2.08 V for the lead storage battery. (a) 2.10 V (b) 2.24 V (c) 2.16 V (d) 2.12 V (e) not enough inf

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  1. 26 September, 09:03
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    d) 2.12 V

    Explanation:

    E = E° - RT/nF log 1/H⁺ x HSO₄⁻

    E = 2.08 - (.059/2 X log 1/4.5x4.5)

    2.08 - (-0.038) = 2.118 = 2.12 V
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