Ask Question
13 September, 06:36

A 26.0-kg block is initially at rest on a horizontal surface. A horizontal force of 72.0 N is required to set the block in motion, after which a horizontal force of 58.0 N is required to keep the block moving with constant speed. (a) Find the coefficient of static friction between the block and the surface. (b) Find the coefficient of kinetic friction between the block and the surface.

+3
Answers (1)
  1. 13 September, 09:32
    0
    a) μ = 0.283, b) μ = 0.228

    Explanation:

    For this exercise we must use the translational equilibrium conditions in each exercise

    Y Axis

    N - W = 0

    N = W = mg

    X axis

    F - fr = 0

    F = fr

    friction force has an expression

    Fr = μ N

    we substitute

    F = μ mg

    μ = F / mg

    let's calculate

    a) μ = 72.0 / 26.0 9.8 static

    μ = 0.283

    b) μ = 58/26 9.8 dinamicic

    μ = 0.228
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A 26.0-kg block is initially at rest on a horizontal surface. A horizontal force of 72.0 N is required to set the block in motion, after ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers