In physics how much energy is required to raise the temp of 9.78kg of water from 40.82c to 52.07c? The specific heat of water in this state is 4186j/kg-c.

469.6KJ

Explanation:

Heat energy required can be calculated using the formula

H = mc∆t where

m is the mass of the water

c is the specific heat capacity of the water

∆t is the change in temperature of the water

Given m = 9.78kg

c = 4186j/kg-c.

∆t = 52.07°C - 40.82°C

∆t = 11.25°C

H = 9.78 * 4186 * 11.25

H = 460,564.65Joules

= 460.6KJ

the amount of energy required to raise the temperature of the water is 460564.65 J

Explanation:

The energy required to raise the temperature of water can be calculated as follows;

Q = mcΔθ

where;

Q is the quantity of heat or energy required to raise the temperature of water

m is mass of water

c is specific heat capacity of water

Δθ is change in temperature = T₂ - T₁

Given;

m = 9.78kg

c = 4186j/kg-c

Δθ = T₂ - T₁ = 52.07°C - 40.82°C = 11.25°C

Q = mcΔθ

Q = (9.78) (4186) (11.25)

Q = 460564.65 J

Therefore, the amount of energy required to raise the temperature of the water is 460564.65 J