1.9 kg block of iron at 24 °C is rapidly heated by a torch such that 14 kJ is transferred to it. What temperature would the block of iron reach (assuming the complete transfer of heat and no loss to the surroundings) ? If that same amount of heat (14 kJ) was quickly transferred to a 810 g pellet of copper at 24 °C, what temperature would the copper reach before it begins losing heat to the surroundings?

Cs, Fe (s) = 0.450 J/g*C

Cs, Cu (s) = 0.385 J/g*C

For iron, T2 = 40.4 degree C

For copper, T2 = 68.89 degree C

Explanation:

For iron:

m = 1.9 kg, T1 = 24 C, Q = 14 kJ = 14000 J, c = 0.450 J / g C = 450 J / Kg C

Let T2 be the final temperature of iron.

Q = m x c x (T2 - T1)

14000 = 1.9 x 450 x (T2 - 24)

T2 = 40.4 degree C

For copper:

m = 810 g = 0.81 kg, T1 = 24 C, c = 0.385 J / g C = 385 J / Kg C, Q = 14 KJ

Let T2 be the final temperature of copper

Q = m x c x (T2 - T1)

14000 = 0.81 x 385 x (T2 - 24)

T2 = 68.89 degree C