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20 May, 22:32

A circular coil of wire of 200 turns and diameter 6 cm carries a current of 7 A. It is placed in a magnetic field of 0.90 T with the plane of the coil making an angle of 30° with the magnetic field. What is the torque on the coil?

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  1. 21 May, 02:22
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    3.08 Nm

    Explanation:

    N = 200, diameter = 6 cm, radius = 3 cm, I = 7 A, B = 0.90 T, Angle = 30 degree

    The angle made with the normal of the coil, theta = 90 - 30 = 60 degree

    Torque = N I A B Sin Theta

    Torque = 200 x 7 x 3.14 x 0.03 x 0.03 x 0.90 x Sin 60

    Torque = 3.08 Nm
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