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9 January, 08:23

you slide across home plate during baseball game. If you have a mass of 82 kg, and the coefficient of kinetic friction between you and the ground is 0.45, what is the force of friction acting on you?

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Answers (2)
  1. 9 January, 09:24
    0
    m = mass of the person = 82 kg

    g = acceleration due to gravity acting on the person = 9.8 m/s²

    F = normal force by the surface on the person

    f = kinetic frictional force acting on the person by the surface

    μ = Coefficient of kinetic friction = 0.45

    The normal force by the surface in upward direction balances the weight of the person in down direction, hence

    F = mg eq-1

    kinetic frictional force on the person acting is given as

    f = μ F

    using eq-1

    f = μ mg

    inserting the values

    f = (0.45) (82) (9.8)

    f = 361.6 N
  2. 9 January, 12:12
    0
    362 rounded, a p e x users
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