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25 February, 10:45

A machine gun fires 33 g bullets at a speed of 342 m/s. The gun fires 115 bullets/min. What is the average force the shooter must exert to keep the gun from moving?

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  1. T
    25 February, 14:43
    0
    The average force that the shooter must exert to prevent the weapon from moving is 21.7 Newtons.

    Explanation:

    m=33g=0,033kg

    V = 342 m/seg

    115 bullets/min = 1 bullet every 0.52 seconds.

    By the principle of momentum and amount of movement we have to:

    F*t=m*V

    F = (m*V) / t

    F = (0.033kg * 342 m/s) / 0.52 sec

    F = 21.7 Newtons
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