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24 August, 18:22

A projectile is launched at ground level with an initial speed of 45.0 m/s at an angle of 30^o (30 degree) above the horizontal. It strikes a target above the ground 2.5 seconds later. What are the and distances from where the projectile was launched to where it lands

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  1. 24 August, 20:49
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    103.32 m

    Explanation:

    From the question, The distance from where the projectile was lunched to where its land is the range (R) of the projectile

    R = (U²sin2 Ф) / g ... Equation 1

    Where U = initial velocity of the projectile, Ф = angle above the horizontal, g = acceleration due to gravity.

    Given: U = 45 m/s, Ф = 30°

    Constant: g = 9.8 m/s²

    Substitute these values into equation 1

    R = (45²sin30°) / 9.8

    R = 2025 (0.5) / 9.8

    R = 103.32 m.
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