A person is standing on a level floor. His head, upper torso, arms, and hands together weigh 496 N and have a center of gravity that is 1.37 m above the floor. His upper legs weigh 199 N and have a center of gravity that is 0.711 m above the floor. Finally, his lower legs and feet together weigh 81.2 N and have a center of gravity that is 0.284 m above the floor. Relative to the floor, find the location of the center of gravity for the entire body.

Question

Physics

Finley Pitts

22 February, 00:40

A person is standing on a level floor. His head, upper torso, arms, and hands together weigh 496 N and have a center of gravity that is 1.37 m above the floor. His upper legs weigh 199 N and have a center of gravity that is 0.711 m above the floor. Finally, his lower legs and feet together weigh 81.2 N and have a center of gravity that is 0.284 m above the floor. Relative to the floor, find the location of the center of gravity for the entire body.

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Answers (1)

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Abagail · Answer 1

Answer: 1.09 m

Explanation:

Given

Weight of the body, W1 = 496 N

Weight of his upper legs, W2 = 199 N

Weight of his lower legs, W3 = 81.2 N

Center of gravity of the body, y1 = 1.37 m

Center of gravity of the upper legs, y2 = 0.711 m

Center of gravity of the lower legs, y3 = 0.284 m

Center of gravity relative to the floor, y (f) = ?

y (f) = (W1y1 + W2y2 + W3y3) / (W1 + W2 + W3), substituting the values, we have

y (f) = [ (496 * 1.37) + (199 * 0.711) + (81.2 * 0.284) ] / (496 + 199 + 81.2)

y (f) = (679.52 + 141.489 + 23.0608) / 776.2

y (f) = 844.0698 / 776.2

y (f) = 1.09 m