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21 December, 04:14

Two charged ping-pong balls separated by a distance of 1.63 m exert an electric force of 0.0224 N on each other. What will be the force if the objects are brought closer, to a separation of only 24.0 cm? (in N)

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  1. 21 December, 05:20
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    Answer: 1.024 N

    Explanation:

    Step 1:

    Using Coulomb's law: F=kQ1Q2/d^2

    We can rearrange the terms to get:

    kQ1Q2=Fxr^2

    Substituting: kQ1Q2=0.0224N x (1.63m) ^2

    Thus kQ1Q2=0.0595

    We know that this value will not change when the balls are brought closer together.

    Step 2:

    Change from cm to m : 1cm=0.01m

    24cm=0.24 m

    Substitute into the new distance and the calculated value for kQ1Q2 into the coulomb law formula to calculate the new force

    F=kQ1Q2/d^2=0.059 / (0.24) ^2

    F=1.024N
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