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28 September, 05:46

You are in a canyon and yell across. It takes 4 seconds for the

echo to come back to you. How wide is the canyon?

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  1. 28 September, 06:06
    0
    Width = 680 [m]

    Explanation:

    To solve this problem we must know the speed of sound in the air, conducting an internet search, we find that this speed has a value of v = 340 [m/s].

    We apply the following kinematic equation, which relates space to time, to define speed.

    v = x / t

    where:

    x = distance [m]

    t = time [s]

    v = velocity [m/s]

    Now replacing:

    x = 340 * 4

    x = 1360 [m]

    But the width of the cannon is calculated when the sound wave hits the wall of the canyon, so this width is half the distance.

    Width = 1360 / 2 = 680 [m]
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