A driver moves with initial velocity of 40m/s accelerates uniformly at a rate of 12m/s2. It attains a velocity 52m/s. calculate the distance covered during the journey.

distance=46m

Explanation:

initial velocity (u) = 40m/s

final velocity (v) = 52m/s

acceleration=12m/s²

distance (s) = ?

v²=u²+2as (using equ. of motion)

(52) ² = (40) ²+2 (12) s

2704=1600+24s

24s=2704-1600

24s=1104

s=1104/24

s=46m