Ask Question
18 August, 17:52

Mercury has a mass of 3.3 e 23 kg and a radius of 2.44 e 6 m. Find Mercury's

gravitational field strength. Show your work (formula, rearrangement, work, answer,

unit, sig dig) (4)

12. Venus has a mass of 4.87 e 24 kg and a radius of 6.05 e 6 m. The gravitational field strength at the surface of Venus is what? m/s2

13. A small Styrofoam ball has a 2.26 nC charge (2.26 x 10°C). Find the electric field strength

5.00 cm (0.0500 m) from the ball. Show your work complete with formula, work, unit and

sig digs) (4)

+5
Answers (1)
  1. 18 August, 21:35
    0
    11.) g = 3.695 m/s^2

    12.) g = 8.879 m/s^2

    13.) E = 8127 N/C

    Explanation:

    11.) Given that the

    Mercury mass M = 3.3 * 10^23kg

    Radius r = 2.44 * 10^6 m

    Gravitational constant G = 6.67408 * 10^-11 m3kg-1 s^-2

    Gravitational field strength g can be calculated by using the formula below

    g = GM/r^2

    Substitutes all the parameters into the formula

    g = (6.67408 * 10^-11 * 3.3 * 10^23) / (2.44*10^6) ^2

    g = 2.2*10^13/5.954*10^12

    g = 3.695 m/s^2

    12.) Given that the

    Venus mass M = 4.87*10^24kg

    Radius r = 6.05 * 10^6 m

    Using the same formula for gravitational field strength g

    g = GM/R2

    Substitute all the parameters into the formula

    g = (6.67408 * 10^-11 * 4.87*10^24) / (6.05*10^6) ^2

    g = 3.25*10^14/3.66*10^13

    g = 8.879 m/s^2

    13.) Given that the

    Charge = 2.26 nC = 2.26*10^-9

    Distance d = 0.05m

    Electric field strength E can be calculated by using the formula below

    E = Kq/d^2

    Where

    K = electrostatic constant 8.99 * 10^9 Nm2/C2

    Substitutes all the parameters into the formula

    E = (8.99 * 10^9 * 2.26*10^-9) / 0.05^2

    E = 20.3174/2.5*10^-3

    E = 8126.96 N/C
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Mercury has a mass of 3.3 e 23 kg and a radius of 2.44 e 6 m. Find Mercury's gravitational field strength. Show your work (formula, ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers