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19 April, 18:33

Jim strikes a 0.058 kg golf ball with a force of 272 N, giving it a velocity of 62.0 m/s. How long was the ball in contact with the club?

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  1. 19 April, 20:32
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    Answer: 0.013 seconds

    Explanation:

    Given that

    Mass of golf ball = 0.058 kg

    Force = 272 N

    Velocity = 62.0 m/s

    Time taken = ?

    Recall that force is the rate of change of momentum per unit time

    i. e Force = Change in momentum / Time

    i. e Force = (Mass x velocity) / Time

    272N = (0.058 kg x 62.0 m/s) / Time

    272N = 3.6kgm/s / Time

    Time = (3.6kgm/s / 272N)

    Time = 0.013 seconds

    Thus, the ball was in contact with the club for 0.013 seconds
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