Suppose an automobile has a kinetic energy

of 2300 J.

When it moves with six times the speed,

what will be its kinetic energy?

Answer in units of J.

Given that,

Kinetic energy of an automobile is 2300J

K. E = 2300J

The formula for kinetic energy is

K. E = ½mv²

So, if the speed of the automobile is increased by 6, what is the kinetic energy

Now v' = 6v.

The mass of the automobile is constant.

Therefore, the kinetic energy is

K. E' = ½mv'²

Where v' = 6v

K. E' = ½m (6v) ²

K. E' = ½m * 36v²

K. E' = 36 * ½mv²

Where, from above ½mv² = 2300J

Then,

K. E' = 36 * 2300 = 82,800J

The kinetic energy of the automobile when it increase it's speed is 82,800J