A titanium cube contains 3.5 * 1023 atoms. the density of titanium is 4.50 g/cm3 part a what is the edge length of the cube?

Answer: 0.92 cm

Explanation:

1) Equations:

Cube shape ⇒ volume = (side length) ³ ⇒ side length = ∛ (volume) Density = mass / volume ⇒ volume = mass / density mass = number of moles * atomic mass atomic mass of titanium = 47.867 g/mol number of moles = number of atoms / Avogadro's number Avogadro's number = 6.022*10²³

2) Calculations:

number of moles = 3.5*10²³ atoms / (6.022*10²² atoms/mol) = 0.58 moles ⇒ mass = 0.58 moes * 47.867 g/mol = 3.49 g ⇒ volume = 3.49g / 4.50 g/cm³ = 0.78 cm³ ⇒ side = √ (0.78cm³) = 0.92 cm ← answer