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13 September, 04:38

A runner starts from rest and accelerates uniformly to a speed of 8.0 meters per

second in 4.0 seconds. The magnitude of the acceleration of the runner is

O

32 m/s/s

o

9.8 m/s/s

O

2.0 m/s/s

O 0.50 m/s/s

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Answers (2)
  1. 13 September, 05:07
    0
    2m/s2

    Explanation:

    a = v - u / t

    Since the runner starts from rest, initial velocity u is Zero

    Final velocity v = 8.0m/s

    Time = 4.0secs

    a = 8.0 - 0 / 4.0

    a = 8.0/4.0

    a = 2m/s2
  2. 13 September, 06:01
    0
    Magnitude of acceleration is 2 m/s²

    Explanation:

    Here, the speed or velocity of the runner = 8 m/s and time = 4 s. Using these values, the magnitude of the acceleration has to be found. Acceleration is given by a = velocity/time

    ⇒ Acceleration = 8/4 = 2 m/s²

    So the magnitude of acceleration is 2 m/s²
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