0.5 kg of silver increases temperature from 0 celsius to 7 celsius when heat is added how much heat energy produced this change in temperature

Recall the equation relating an object's change in thermal energy to its change in temperature:

ΔQ = mcΔT

ΔQ is the change in thermal energy.

m is the mass of the object.

c is the object's specific heat.

ΔT is the object's change in temperature.

Given values:

m = 0.5 kg = 500g

ΔT = (7-0) ⁰C = 7°C

Online sources say the specific heat of silver is 0.240 J/g⁰C

Substitute the terms in the equation with the given values and solve for ΔQ:

ΔQ = 500*0.240*7

ΔQ = 840 J