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27 October, 04:16

We want to hang a thin hoop on a horizontal nail and have the hoop make one complete small-angle oscillation each 2.0 s. What must the hoop's radius be?

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  1. 27 October, 08:10
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    Given that the hoop makes one complete oscillation in 2s, this implies that the period of oscillation is 2s

    Then,

    T = 2s

    Let Mass of the thin hoop be M

    Let Radius of the hoop be R

    Moment of inertial of a hoop is

    I = MR²

    Period of a physical pendulum of small amplitude is given by

    T = 2π √ (I / Mgd)

    Where,

    T is the period in seconds

    I is the moment of inertia in kgm²

    M is the mass of the hoop

    g is the acceleration due to gravity

    g = 9.8m/s²

    d is the distance from rotational axis to center of of gravity

    Therefore, d = R

    Then, applying the formula

    T = 2π √ (I / MgR)

    So, we know that

    I = MR²

    Then,

    T = 2π √ (MR² / MgR)

    T = 2π √ (R/g)

    Make R subject of formula

    Square both sides

    T² = 4π² (R/g)

    T²g = 4π²R

    Then, R = T²g / 4 π²

    Since g = 9.8m/s² and T = 2s

    R = 2² * 9.8 / 4π²

    R = 0.993m

    Then, the radius of the hoop is 0.993m
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