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12 September, 20:21

A solid disc with a radius of 5.00 m and a mass of 20.0 kg is initially at rests and lies on the plane of the paper. A smaller solid disc with a radius of 2.50 m and a mass of 10.0 kg is spinning at 3500. rpm. The smaller disc is carefully pressed against the larger disc (flat side to flat side) so that they spin together without slipping. What is the angular velocity of the large disc

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  1. 12 September, 23:24
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    This problem is based on conservation of angular momentum.

    moment of inertia of larger disc I₁ = 1/2 m r², m is mass and r is radius of disc. I

    I₁ =.5 x 20 x 5²

    = 250 kgm²

    moment of inertia of smaller disc I₂ = 1/2 m r², m is mass and r is radius of disc. I

    I₂ =.5 x 10 x 2.5²

    = 31.25 kgm²

    3500 rmp = 3500 / 60 rps

    n = 58.33 rps

    angular velocity of smaller disc ω₂ = 2πn

    = 2π x 58.33

    = 366.3124 rad / s

    applying conservation of angular momentum

    I₂ω₂ = (I₁ + I₂) ω, ω is the common angular velocity

    31.25 x 366.3124 = (250 + 31.25) ω

    ω = 40.7 rad / s.
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