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8 May, 09:45

An initially stationary object experiences an acceleration of 6 m/s2 for a time of 15 s. How far will it travel during that time?

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  1. 8 May, 13:40
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    Distance = (intial speed) X (Time) + 1/2 (acceleration) X (Time) [Third equation of motion]

    As initial speed is zero, therefore;

    Distance = 1/2 (acceleration) X (Time)

    = 1/2 (6 X 15)

    = 1/2 (90)

    = 45 meters

    Hence, the object traveled 45 meters.
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