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16 August, 10:47

A 206.3 kg walrus initially at rest on a horizontal floor requires a 249 N horizontal force to set it in motion. Find the coefficient of static friction between the walrus and the floor. Use 10 m/s2 for g.

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  1. 16 August, 14:26
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    Maximum friction force = 249 N

    Normal reaction force=206.3*10=2063 N

    Maximum friction force=coefficient of friction*normal reaction force

    Maximum friction force/normal reaction force=coefficient of friction

    Coefficient of friction=249/2063=0.121
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