Ask Question
24 February, 23:37

compute the value of the magnifying power of a 150-inch fl8 telescope with an eyepiece of one-half-inch focal length

+3
Answers (2)
  1. 25 February, 02:18
    0
    assume fl8 is f/8

    150" at f/8 means the focal length = 150*8 = 1200 inches

    divide by eyepiece of 1/2", the magnifying power = 1200 / (1/2) = 2400X
  2. 25 February, 02:26
    0
    150 inches at f/8 gives a focal length of 1200 inches.

    Divide 1200 inches by 1/2 inch eye piece to get the magnification of 2400x.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “compute the value of the magnifying power of a 150-inch fl8 telescope with an eyepiece of one-half-inch focal length ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers