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18 January, 20:07

Calculate the final velocity right after a 117 kg rugby player who is initially running at 7.45 m/s collides head‑on with a padded goalpost and experiences a backward force of 17700 N for 5.50*10-2 s

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  1. 18 January, 22:19
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    v_f = 0.87 m/s

    Explanation:

    We are given;

    F_avg = - 17700 N (negative because it's backward)

    m = 117 kg

    Δt = 5.50 * 10^ (-2) s

    v_i = 7.45 m/s

    Now, formula for impulse is given by;

    I = F•Δt = - 17700 x 5.50 * 10^ (-2) = - 973.5 kg. m/s

    From impulse momentum theory, we know that;

    Change in momentum of particle is equal to impulse.

    Thus,

    Δp = I = m•v_f - m•v_i

    Thus,

    -973.5 = 117 (v_f - 7.45)

    Thus,

    -973.5/117 = (v_f - 7.45)

    -8.3205 + 7.45 = v_f

    v_f = - 0.87 m/s

    We'll take absolute value as;

    v_f = 0.87 m/s
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