0.5kg ball moving at a speed of 3m/s rolls up a hill what is thet height

According to conservation of energy

Kinetic energy at the bottom of hill = potential energy at top of hill

Kinetic energy (KE) = 0.5*mass (m) * velocity (v) ²

where m=0.5 kg, and v = 3 m/s, v²=9

KE=0.5*0.5*9=2.25 J = PE

PE=m*gravitational acceleration (g) * height (h)

h=2.25 / (0.5*9.8) = 0.459 m