Jason hits a volleyball with an initial velocity of 6 meters per second straight up. if the back starts at 2 meters above the floor how long will the ball be in the air

Vi = 6 m/s

d = - 2 m

a = - 9.81 m/s^2

t = ?

Formula

d = vi*t + 1/2 a t^2

- 2 = 6m/s * t -.5 * 9.81 * t^2

Put the - 2 on the right.

4.905 t^2 + 6 m/s t + 2 = 0

a = - 4.905 m/s^2

b = 6 m/s

c = 2 m

t = [ - b + / - square root (b^2 - 4ac) ] / (2a)

t = [ - 6 + / - square root (6^2 - 4 * (-4.905) * 2) ] / ( - 4.905*2)

t = [-6 + / - 8.674) / - 9.81

t = - 14.674/-9.81

t = 1.69 seconds.