A 65 ml sample of argon gas has a temperature of 325 °c. what will the temperature be in °c when the volume of the gas is decreased to 25 ml at constant pressure?

A law of gas that expresses the relationship between the volume and the temperature of a gas at a constant pressure is called the Charle's law.

Charles' Law states that the volume of a fixed mass of a gas is directly proportional to the temperature at a constant pressure.

Mathematically, Charles law can be stated thus: V1 / T1 = V2 / T2

Here, V1 = 65ml, T1 = 325 C, V2 = 25ml T2 = ?

So, 65 / 325 = 25 / T2

65 x T2 = 325 x 25 = 8125

T2 = 8125 / 65 = 125 C

Therefore, the temperature of the gas in degree C when the volume is decreased to 25 ml at constant pressure is 125 degree C.