What volume in milliliters will 0.00922 g of h2 gas occupy at stp?

Question

Physics

Josh Barrera

28 October, 23:33

What volume in milliliters will 0.00922 g of h2 gas occupy at stp?

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Answers (1)

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Francis Mcmahon · Answer 1

Assuming that this gas is in ideal state, we can use the relation that for every 1 mol of an ideal gas it would have a volume of 22.4 L. But before using this, relation we need to convert the number of grams of H2 into moles by using the molar mass of 2.02 g/mol.

moles H2 = 0.00922 g (1 mol / 2.02 g) = 0.005 mol H2

Volume H2 at STP = 0.005 mol H2 (22.4 L / 1 mol) = 0.102 L of H2