Ask Question
14 January, 04:48

On a road trip, a driver achieved an average speed of (48.0+A) km/h for the first 86.0 km and an average speed of (43.0-B) km/h for the remaining 54.0 km. What was her average speed (in km/h) for the entire trip? Round your final answer to three significant figures. A = 15 B = 1

+3
Answers (1)
  1. 14 January, 05:28
    0
    A = 15, B = 1

    48 + 15 = 63 for the first 86km

    43 - 1 = 42 for the remaining 54 km

    time = distance/speed

    t1 = 86/63 = 1.3651hours

    t2 = 54/42 = 1.2857hours

    speed = distance/time

    s = 140/2.6508

    average speed = 52.8km/h
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “On a road trip, a driver achieved an average speed of (48.0+A) km/h for the first 86.0 km and an average speed of (43.0-B) km/h for the ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers