A line from the Brackett series of hydrogen has a wavelength of 1945nm (or 1.0979x10^7m). From which state did the electron originate.

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Physics

Elyse Lopez

7 August, 09:41

A line from the Brackett series of hydrogen has a wavelength of 1945nm (or 1.0979x10^7m). From which state did the electron originate.

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Luna Terry · Answer 1

We use the Rydberg Equation for this which is expressed as:

1 / lambda = R [ 1 / (n2) ^2 - 1 / (n1) ^2]

where lambda is the wavelength, where n represents the final and initial states. Brackett series means that the initial orbit that electron was there is 4 and R is equal to 1.0979x10^7m. Thus,

1 / lambda = R [ 1 / (n2) ^2 - 1 / (n1) ^2]

1/1.0979x10^7m = 1.0979x10^7m [ 1 / (n2) ^2 - 1 / (4) ^2]

Solving for n2, we obtain n=1.