A cyclist turns a corner with a radius of 37 m at a speed of 22 m/s. What's the cyclist acceleration? If the cyclist and cycle have a combined mass of 90 kg, what is the force causing them to turn?

Question

Physics

Judith Hess

5 January, 22:43

A cyclist turns a corner with a radius of 37 m at a speed of 22 m/s. What's the cyclist acceleration? If the cyclist and cycle have a combined mass of 90 kg, what is the force causing them to turn?

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Answers (1)

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Giovanna · Answer 1

The cyclist will be experiencing centrifugal acceleration:

Acceleration = m*v²:r

Where:

m = mass

v = velocity of cyclist

r = radius of the corner

Acceleration = 90*22²:37 = 1177.3 m/s²