A snowmobile has an initial velocity of 4.7 m/s.

If it accelerates at the rate of 0.73 m/s2 for 5.6s, what is the final velocity? Answer in units of m/s, If instead it accelerates at the rate of - 0.51 m/s2, how long will it take to reach a complete stop? Answer in units of s ... ?

Q1. The answer is 8.788 m/s

V2 = V1 + at

V1 - the initial velocity

V2 - the final velocity

a - the acceleration

t - the time

We have:

V1 = 4.7 m/s

a = 0.73 m/s²

t = 5.6 s

V2 = ?

V2 = 4.7 + 0.73 * 5.6

V2 = 4.7 + 4.088

V2 = 8.788 m/s

Q2. The answer is 9.22 s

V2 = V1 + at

V1 - the initial velocity

V2 - the final velocity

a - the acceleration

t - the time

We have:

V2 = 0 (because it reaches a complete stop)

V1 = 4.7 m/s

a = - 0.51 m/s²

t = ?

0 = 4.7 + (-0.51) * t

0 = 4.7 - 0.51t

0.51t = 4.7

t = 4.7 / 0.51

t = 9.22 s