If a 990 kg car is on the road and the Ff is 360 n what is the normal force

Given that a car is in the road, there is only movement in the x-direction. There is no movement in the y-direction.

Looking at the y-direction for the normal force:

F = N - mg

0 = N - mg, (no movement in y-dir.)

N = mg

N = (990) (9.8)

N = 9702 newtons

The normal force exerted on the car by the road is 9702 newtons.