Ask Question
2 August, 11:43

A 1451 kg car is traveling at 48.0 km/h.

How much kinetic energy does it possess? K. E. =

1.67 x 105 J

9.65 x 105 J

1.28 x 105 J

3.48 x 105 J

+2
Answers (2)
  1. 2 August, 11:54
    0
    Would be a. since KE = 1/2 m*v^2
  2. 2 August, 13:43
    0
    KE = (1/2) · (1,451 kg) · (48 km/hr) ² · (1000 m/km) ² · (1 hr/3,600 sec) ²

    = (725.5) · (48 · 1000 · 1 / 3,600) ² (kg) · (km·m·hr / hr·km·sec) ²

    = (725.5) · (40/3) ² · (kg·m² / sec²)

    = 128,978 joules (rounded)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A 1451 kg car is traveling at 48.0 km/h. How much kinetic energy does it possess? K. E. = 1.67 x 105 J 9.65 x 105 J 1.28 x 105 J 3.48 x 105 ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers