A stone was dropped off a cliff and hit the ground with a speed of 96 ft/s. What is the height of the cliff? (Use 32 ft/s2 for the acceleration due to gravity.)

Question

Physics

Blaze Page

31 August, 02:49

A stone was dropped off a cliff and hit the ground with a speed of 96 ft/s. What is the height of the cliff? (Use 32 ft/s2 for the acceleration due to gravity.)

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Taylor Buckley · Answer 1

The initial velocity of the stone is 0 ft/s. Given the initial velocity (Vi), final velocity (Vf), and acceleration due to gravity (g), the distance may be calculated through the equation,

d = ((Vf) ² - (Vi) ²) / 2g

Substituting the known values,

d = ((96 ft/s) ² - 0)) / (2x32.2)

The value of d is 143.10 ft.