Calculate the energy transferred in joules when 29.5g of liquid water decreases from 14c to 0.0c

The energy transferred in joules is calculated using the below formula

Q (heat energy) = M (mass) x C (specific heat capacity) x delta T (change in temperature

delta T = 0. 0c - 14 c = - 14 c

M = 29.5 g

C of water is always = 4.18 j/g/c

= 29.5 g x - 14 c x 4.18 j/g/c = - 1726.34 joules are needed when 29.5 g of liquid water decrease from 14 c to 0.0 C